Directions: Given an array and chunk size, divide the array into many subarrays where each subarray is of length size.

Examples:

chunk([1, 2, 3, 4], 2) --> [[ 1, 2], [3, 4]]
chunk([1, 2, 3, 4, 5], 2) --> [[ 1, 2], [3, 4], [5]]
chunk([1, 2, 3, 4, 5, 6, 7, 8], 3) --> [[ 1, 2, 3], [4, 5, 6], [7, 8]]
chunk([1, 2, 3, 4, 5], 4) --> [[ 1, 2, 3, 4], [5]]
chunk([1, 2, 3, 4, 5], 10) --> [[ 1, 2, 3, 4, 5]]

For the first example, you have an array, and a chunk with a size of 2. Therefore, the array should be broken up into CHUNKS of 2 elements.

Solution 1:

Create empty array to hold chunks called 'chunked'
For each element in the array...
1. retrieve the last element in the chunked array
2. IF last element does not exists, or if its length is equal to the chunk size
  - push a new chunk into the chunked array
3. Else add the current element to the last element in the chunked array

function chunk(array, size) {
  const chunked = []

  for (let char of array) {
    const last = chunked[chunked.length - 1] // get last character in array

    if (!last || last.length === size) {
      //   if no last element, or length of chunk is size,
      chunked.push([char]) // <------------ push a new chunk containing the char to chunked array
    } else {
      last.push(char) // <----------------- push character into the last chunk
    }
  }

  return chunked
}

Solution 2: while-loop & slice()

Slice() Syntax:

slice()
slice(start)
slice(start, end)

function chunk(array, size) {
  // option 2 with slice()
  const chunked = []
  let index = 0
  while (index < array.length) {
    chunked.push(array.slice(index, index + size))
    index = index + size
  }
  return chunked
}